Question

te^-t^2
chain rule Im not sure of the steps.
thanks

Answer 1

What do you want to do? Integrate that function?

Answer 2

differentiate

Answer 3

so, it's \[\frac{d(te^{-t^2})}{dt}\]

Answer 4

well yes using the chain rule

Answer 5

use product rule first. Can you?

Answer 6

well I was trying to do that first but it didnt work

Answer 7

\[f'(t)=e^{-t^2}+t\frac{de^{-t^2}}{dt}\] now we use chain rule to find \[\frac{de^{-t^2}}{dt}\]

Answer 8

I was kidding, we can't use chain rule only here.