A short stop makes an error by dropping the ball. As the ball drops, its height h in feet as a function of time, t, is modeled by h(t) = -16t2 + 3. A slow motion replay of the error shows the play at half speed. What function describes the height of the ball in the replay? (Hint: The function squares the time, so half the time is also squared in the new function.)

I'm not sure where to start..
the answers are:

A.) V\h(t) = (-16t^2 + 3)/2
B.) h(t) = -8(t)^2 + 3
C.) h(t) = -16(0.5t)^2 + 1.5
D.) h(t) = -16(t/2)^2 + 3

Question

A short stop makes an error by dropping the ball. As the ball drops, its height h in feet as a function of time, t, is modeled by h(t) = -16t2 + 3. A slow motion replay of the error shows the play at half speed. What function describes the height of the ball in the replay? (Hint: The function squares the time, so half the time is also squared in the new function.)

I'm not sure where to start..
 the answers are:

A.) V\h(t) = (-16t^2 + 3)/2
B.) h(t) = -8(t)^2 + 3
C.) h(t) = -16(0.5t)^2 + 1.5
D.) h(t) = -16(t/2)^2 + 3

anonymous · Answer

If we solve for the time when the ball hits the ground (in real time), we get t = (sqrt3)/4.  If we solve equation D in the same way, we get t = (sqrt3)/2, exactly twice as long.