Question

Two blocks are connected by a thin inexten- sible string over a frictionless massless pulley as shown on the picture below The acceleration of gravity is 9.8 m/s2 . 58 kg weight of box hanging from pulley 36 kg weight of box on ramp v = 6.1 m/s a = 1.1 m/s2 @39 Degrees Given that the two blocks move at 6.1 m/s under an acceleration of 1.1 m/s2, calculate the coefficient μk of kinetic friction between the left block and the incline.

Answer 1

the equation that i found was
T-mgcos(theta)+Mu times mgcos(theta)=ma

then cancel all the masses

T-gcostheta+Mu x gcostheta=a
T-gcostheta+gcostheta-a=mu

Answer 2

T-gsin(theta)+gcostheta-a= mu