Question

find partial derivative Hx and Hy of H(x,y)=(y^2+1)e^x

Answer 1

can you explain how you find the partial derivative with respect to x? Short sentance...

Answer 2

you basically do derivative just with respect to x and treating y as a constant

Answer 3

So Mproof, Hmm If you take partials, you'll be treating the OTHER variable as a constant, meaning you won't have the product rule as it might seem at first glance.
Does that help? :O

Answer 4

like 3x^2y+2 fx=6xy and Fy is 3x^2

Answer 5

right. So what is confusing you about this problem?

Answer 6

would Hx be 0?

Answer 7

no. What is the regular derivative of f(x) = e^x?

Answer 8

same

Answer 9

Think of the equation as Ce^x when taking the partial WRT x. Maybe that will help :)

Answer 10

but don't you have to take a derivative of the (y^2+1) with respect to x?

Answer 11

no, thats just a constant attached to e^x :d

Answer 12

Maybe one thing you can do to convince yourself is, distribute the e^x to each term in the brackets.
Then think about what you have :o

Answer 13

so the derivative with respect to x will be the same as the given problem

Answer 14

ya :) good

Answer 15

ooo I get it

Answer 16

with respect to Y would it be 2ye^x?

Answer 17

(y^2 + 1)e^x = y^2 e^x + e^x
Hy = 2y e^x + 0

Yes, very good ^^