Question

Evaluate the following integral.

integrate from -1 to 1 (x)/(x^2+2x+1)dx

This is what I got so far
using partial fractions I got

= A/(x+1) + B/(x+1)^2
x = A(x+1)^2+B(x+1)
not sure if this is right but I am stuck here.

Answer 1

just A(x+1) + B = x

Answer 2

remember you're, in effect, 'finding the CD'

\[\frac{ A }{x+1} + \frac{ B }{ (x+1)^2 }\]
\[\frac{ A }{x+1} *\frac{ (x+1) }{ (x+1) }+ \frac{ B }{ (x+1)^2 } = \frac{ x}{ (x+1)^2 } \]

Answer 3

Ah yes good catch Alg! :D
Your initial setup looks good max, but when you multiplied through by the denominator, those terms should have simplified down a little bit more.

Answer 4

Thanks for the help thats the nudge I needed and I was able to solve the problem.