Question

A racecar starting from rest accelerates uniformally at rate of 4.90 meters per second^2. What is the cars speed after it has traveled 200. meters?

Answer 1

ok.., using this formula:
vt^2 = vo^2 + 2 a.s;
where s = 200 m, a = 4.90 m/s^2, and Vo = 0;

The cars speed after is has traveled 200 is:
vt^2 = 0 + (2x 4.90 x 200)
vt^2 = 980
vt = sqrt (1960)
vt = 44.2718 m/s

Done ! :) please correct me if I wrong

Answer 2

what does vo stand for?

Answer 3

and vt as well?

Answer 4

vo is initial velocity of racecar.., and vt is the final speed

Answer 5

oh okay, thank you so much!!!

Answer 6

ur welcome :)