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Let f(x)=x^(4x) find f'(x)
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Hmmmmm an x in the base, AND in the exponent... Looks like we'll have to apply good ole logarithmic differentiation for this one :D
Step 1, let y=f(x), then take the natural log of both sides. Understand how to do that? :D
Had an exam question like that and really screwed it up. Make sure you know how to do this!!!
I am still confused. sorry.
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