Question

[solve for x] m_1(x)=m_2(3-x)

Answer 1

So if I understand your question correctly it looks like this:
\[m_{1}=m_{2}(3-x)\] Is that the correct format for the question your working on?
If it is, then you could divide both sides by:
\[m_{2}\]
That should put you in a position to start getting x by itself. If that isn't helpful please let me know and I'll see if I can give you another hint.

Answer 2

\[m _{1} (x) =m _{2}(3-x)\]

Answer 3

can you give me another hint

Answer 4

Yes, sorry it took me a moment to get back to you. Just a moment while I think of a hint.

Answer 5

So if we divide both sides as I've suggested we end up with a form that looks like this:
\[\frac{ m_{1} }{ m_{2} }=3-x\]Now we need to get that x by itself correct? What are some of the things you can do to both sides of an equation? You can multiply both sides by a number or add or subtract the same number to both sides. So for exammple, if I multilply both sides by -1, OR instead of doing that I subtract both sides by 3. It begins to get x by itself.

Does that help?

Answer 6

yes it does thank you very much

Answer 7

Your welcome. :)