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Mathematics 23 Online
OpenStudy (anonymous):

Let f(x)=4lnabsolutevalue(sec(x)+tan(x))

zepdrix (zepdrix):

Oh this is a fun one :) lol

OpenStudy (anonymous):

f'=secx

OpenStudy (cruffo):

\[ \large f(x) = 4\ln\vert\sec(x) + \tan(x)\vert\]

OpenStudy (anonymous):

this is a formula !!

zepdrix (zepdrix):

Yah but he probably needs to do the work mah... -_-

OpenStudy (anonymous):

4 sec x

OpenStudy (cruffo):

He/she hasn't said what they want to do with it :)

zepdrix (zepdrix):

Hmmmmm true :) Find f'(x)? What's up AJ? :D

OpenStudy (anonymous):

Actually it gets even more fun it is find f"(x)

zepdrix (zepdrix):

Are you allowed to use the shortcut that mahmit posted? Or do you need to show all the steps? (This is a derivative that eventually you'll just memorize, that's why i ask)

OpenStudy (anonymous):

it was obvious what he/she wanted !!

OpenStudy (anonymous):

I need to show the steps unfortunately :(

OpenStudy (anonymous):

lu)'=u'/u

OpenStudy (anonymous):

4secxtanx+sec2x/secx+tanx=4secx

OpenStudy (anonymous):

I thought that the derivative sec(x)tan(x) not sec(x)+tan(x) equaled sec(x)

zepdrix (zepdrix):

(secx)'=secx(tanx) Yes that is true, that's where we'll be heading after we find the first derivative. The first derivative unfortunately will give us something rather sloppy, and we'll have to do a little work to simplify it down.

zepdrix (zepdrix):

|dw:1350357014788:dw|

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