Question

logarithmic differentiation

http://gyazo.com/19b7f3bf7c37e447a06247b31fecd8d0

Answer 1

if i put ln on right side, do i have to put ln on left side as well? :l

ex: ln(f(x))=ln(whatever is on right side)

Answer 2

yes.

Answer 3

im not entirely sure if i can just throw in ln on right side and solve

Answer 4

oh ic

Answer 5

if x = y, then ln(x) = ln(y).

Answer 6

did you get the final answer cruffo? '_'

Answer 7

I think so.

Answer 8

post so i can double check my answer when i solve? :)

Answer 9

I got
\[\large \frac{dy}{dx} = -e^{1-x}tan^{-1}(x) + \frac{e^{1-x}}{1+x^2}\]

Answer 10

hmm. im doing it another way. how do i take derivative of ln(tan^-1)?

Answer 11

chain rule..

Answer 12

yh. but how do i take derivivative of just ln?

Answer 13

if y = ln(x), then y' = 1/x

Answer 14

but its ln(tan^-1), not ln(x)

Answer 15

right, so you get (1/tan^-1(x)) * derivative of tan^-1(x)

Answer 16

o wait. think its coming back to me. ic now

Answer 17

:) hehehehe

Answer 18

thanks for the help once again.

Answer 19

np!