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Mathematics 17 Online
OpenStudy (anonymous):

find dy/dx for tan(x+y)=y

OpenStudy (hba):

Use implicit differentiation.

OpenStudy (anonymous):

but should i use the trig identity or not? or just solve with the sec^2(x+y) dy/dx?

OpenStudy (hba):

Well You Would Have To Use Pythagoras Identity In The End,Show Me The Steps And I Will Explain You :)

OpenStudy (hba):

@AJlaxgirl95

OpenStudy (anonymous):

tan(x+y)=y (tan(x)+tan(y))/(1-tan(x)tan(y))=y ((sec^2(x))+((sec^2(y)(dy/dx))/(-sec^2(x) sec^2(y)(dy/dx)) that's as far as i've gotten

OpenStudy (hba):

If x = tan(x + y), then taking d/dx of both sides, we get: dy/dx = sec^2(x + y)*(1 + dy/dx) (using the chain rule)

OpenStudy (anonymous):

so i don't use the trig identity?

OpenStudy (hba):

You Will Use And Identity In The End

OpenStudy (anonymous):

but you solved what i had to solve already i just needed to find what dy/dx equals

OpenStudy (anonymous):

wait nvm

OpenStudy (hba):

No It Has Not Finished Yet LoL

OpenStudy (anonymous):

i get it ^.^

OpenStudy (hba):

Oh Good

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