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find dy/dx for tan(x+y)=y
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Use implicit differentiation.
but should i use the trig identity or not? or just solve with the sec^2(x+y) dy/dx?
Well You Would Have To Use Pythagoras Identity In The End,Show Me The Steps And I Will Explain You :)
@AJlaxgirl95
tan(x+y)=y (tan(x)+tan(y))/(1-tan(x)tan(y))=y ((sec^2(x))+((sec^2(y)(dy/dx))/(-sec^2(x) sec^2(y)(dy/dx)) that's as far as i've gotten
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If x = tan(x + y), then taking d/dx of both sides, we get: dy/dx = sec^2(x + y)*(1 + dy/dx) (using the chain rule)
so i don't use the trig identity?
You Will Use And Identity In The End
but you solved what i had to solve already i just needed to find what dy/dx equals
wait nvm
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No It Has Not Finished Yet LoL
i get it ^.^
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