Question

if 10^50-74 is written as an integer in base 10 notation wat is the sum of the digits in that integer

Answer 1

ans is 440
but how do v solve tis??

Answer 2

(10^4) - 74 = ?
(10^4) - 10*7.4 = ?
10*[(10^3) - 7.4] = ?
10*[10^3 - 7.4] = 992.6*10 = 9926 = 9*2+2+6 = 26
Note that 10^4 will yield two nines a six and a two.
so solving for 10^50 and 74 will give 48 nines a six and a two:
10*[10^49 - 7.4] = 9*48+2+6 = 440

Answer 3

@Fall12-13 wer did u get tis frm i hav the exact soln wid me but didnt get it as in how 10^50 gives 48 nines

Answer 4

Can you post your steps/how you worked the problem? We can see where you're going wrong then.

Answer 5

solve tis 10(10^49-7.4)

Answer 6

You get 48 nines,but the LAST numbers are 2 and 6, we take them in and add them.
10(10^49-7.4)=99999999999999999999999999999999999999999999999926

Answer 7

got it... it was silly ques!!
thanks:)

Answer 8

No problem, nice to know.