Matthew is the ugliest guy in his school. Therefore, the probability that he can have a beautiful girlfriend is 0.001. Suppose he woos 10 beautiful girls at the same time. What is the probability that Matthew can have at least one beautiful girlfriend?
1 - P(he can't have any girlfriend)...?
and that would be...?
P(he can't have any girlfriend) = 1 - P(he can have all girlfriends) maybe.
...you're just looping....
my thoughts... \[\huge 1 - _{10} C _0 \times (0.001)^0 \times (0.999)^{10}\] but a part of me knows this is wrong...
To be clear Suppose he woos a girl, the odds that that girl becomes his girlfriend is 0.001 ?
probability
Then why can't it just be 10 x 0.001? after all, he does it ten times
...because i don't think it's that simple...
@terenzreignz what if it was 100,000 girls..what would the probability be then.
Ok, that was a long shot, too good to be true :)
so i assume you know how to do this @Zarkon ?
yes
am i right?
provided you have some added assumptions...
by that you mean...?
the girls selected are independent from each other and that the .001 applies to all girls equally
then this follows a binomial distribution
and you are correct
wonderful
here's a question out of curiosity....how many girls should he woo to make sure that he can get one of the beautiful girls to be his girlfriend?
infinite..otherwise there will be a positive probability that he will not get one
if you want above a 50% chance then you would need 693
above 90% you would need 2302
is the above 50% the one where he can surely get one of the girls to be his girl?
no
half the time he still would not get one
i think my question is related to that saying "In a group of 23, two of the people will surely have the same birthday" or something
the only way to be 100% positive her would get a girl is to have an infinite number of girls to 'work' on
for the b-day problem the 23 just gives you a slightly better than 50% chance of having a matching birthday. It does not guarantee it
ah yes. that was the saying
is it related?
no..for the b-day problem if you have more that 365 people then you will have at least one match
``` the only way to be 100% positive her would get a girl is to have an infinite number of girls to 'work' on ``` That is more like the infinite monkey theorem!
what about the 5% theorem thing? is it applicable?
not sure what you are referring to
that is a stretch 'p-value' and '5% thing' ;)
p-values are for hypothesis tests
5% is a p-value that was what i was referring to
this is not a hypothesis testing problem
if the probability is less than 5% then it's significant...so i supose here we assume prob to be > 5%
hmm so i suppose nothing fits huh
matthew will have to take his chances
"5% then it's significant." that depends on who you are asking and what is being tested
for medical testing one usually goes much lower than 5%
Join our real-time social learning platform and learn together with your friends!