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Mathematics 17 Online
OpenStudy (lgbasallote):

Matthew is the ugliest guy in his school. Therefore, the probability that he can have a beautiful girlfriend is 0.001. Suppose he woos 10 beautiful girls at the same time. What is the probability that Matthew can have at least one beautiful girlfriend?

Parth (parthkohli):

1 - P(he can't have any girlfriend)...?

OpenStudy (lgbasallote):

and that would be...?

Parth (parthkohli):

P(he can't have any girlfriend) = 1 - P(he can have all girlfriends) maybe.

OpenStudy (lgbasallote):

...you're just looping....

OpenStudy (lgbasallote):

my thoughts... \[\huge 1 - _{10} C _0 \times (0.001)^0 \times (0.999)^{10}\] but a part of me knows this is wrong...

terenzreignz (terenzreignz):

To be clear Suppose he woos a girl, the odds that that girl becomes his girlfriend is 0.001 ?

OpenStudy (lgbasallote):

probability

terenzreignz (terenzreignz):

Then why can't it just be 10 x 0.001? after all, he does it ten times

OpenStudy (lgbasallote):

...because i don't think it's that simple...

OpenStudy (zarkon):

@terenzreignz what if it was 100,000 girls..what would the probability be then.

terenzreignz (terenzreignz):

Ok, that was a long shot, too good to be true :)

OpenStudy (lgbasallote):

so i assume you know how to do this @Zarkon ?

OpenStudy (zarkon):

yes

OpenStudy (lgbasallote):

am i right?

OpenStudy (zarkon):

provided you have some added assumptions...

OpenStudy (lgbasallote):

by that you mean...?

OpenStudy (zarkon):

the girls selected are independent from each other and that the .001 applies to all girls equally

OpenStudy (zarkon):

then this follows a binomial distribution

OpenStudy (zarkon):

and you are correct

OpenStudy (lgbasallote):

wonderful

OpenStudy (lgbasallote):

here's a question out of curiosity....how many girls should he woo to make sure that he can get one of the beautiful girls to be his girlfriend?

OpenStudy (zarkon):

infinite..otherwise there will be a positive probability that he will not get one

OpenStudy (zarkon):

if you want above a 50% chance then you would need 693

OpenStudy (zarkon):

above 90% you would need 2302

OpenStudy (lgbasallote):

is the above 50% the one where he can surely get one of the girls to be his girl?

OpenStudy (zarkon):

no

OpenStudy (zarkon):

half the time he still would not get one

OpenStudy (lgbasallote):

i think my question is related to that saying "In a group of 23, two of the people will surely have the same birthday" or something

OpenStudy (zarkon):

the only way to be 100% positive her would get a girl is to have an infinite number of girls to 'work' on

OpenStudy (zarkon):

for the b-day problem the 23 just gives you a slightly better than 50% chance of having a matching birthday. It does not guarantee it

OpenStudy (lgbasallote):

ah yes. that was the saying

OpenStudy (lgbasallote):

is it related?

OpenStudy (zarkon):

no..for the b-day problem if you have more that 365 people then you will have at least one match

Parth (parthkohli):

``` the only way to be 100% positive her would get a girl is to have an infinite number of girls to 'work' on ``` That is more like the infinite monkey theorem!

OpenStudy (lgbasallote):

what about the 5% theorem thing? is it applicable?

OpenStudy (zarkon):

not sure what you are referring to

OpenStudy (lgbasallote):

http://en.wikipedia.org/wiki/P-value

OpenStudy (zarkon):

that is a stretch 'p-value' and '5% thing' ;)

OpenStudy (zarkon):

p-values are for hypothesis tests

OpenStudy (lgbasallote):

5% is a p-value that was what i was referring to

OpenStudy (zarkon):

this is not a hypothesis testing problem

OpenStudy (lgbasallote):

if the probability is less than 5% then it's significant...so i supose here we assume prob to be > 5%

OpenStudy (lgbasallote):

hmm so i suppose nothing fits huh

OpenStudy (lgbasallote):

matthew will have to take his chances

OpenStudy (zarkon):

"5% then it's significant." that depends on who you are asking and what is being tested

OpenStudy (zarkon):

for medical testing one usually goes much lower than 5%

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