Question

log_1 3(x+5) + log_1 3(x-5) = 2

Answer 1

\[\log_13(x+5) + \log_13(x-5) = 2\]

solve for x:

Answer 2

I would really appreciate if anyone could teach me how to do this question, struggling very hard.

Answer 3

apply logx+logy=logxy

Answer 4

it will come log-1(9*(x^2-25)=2
=> x^2-25=1/9
now solve it for x

Answer 5

Yup......

so...


\[\log_{1} 3(x-5)*3(x+5) = 2\]

Answer 6

\[\log_{1}9(x^2-25) = 2 \]

\[9(x^2-25) = 1^2\]

\[x^2-25 = \frac{ 1 }{ 9 }\]

\[x^2=25+\frac{1 }{ 9 }\]

Answer 7

Nw just Solve for x