Question

ln(x^3-1)-ln(x^2+x+1)

express in single logarithm with coefficient of 1

Answer 1

\[\ln \frac{ (x ^{3}-1) }{x ^{2}+x+1 }\]

Answer 2

now what? do i need to expand the denominator?

Answer 3

x^-1=(x-1)(x^2+x+1)

Answer 4

Better to expand the numerator.

Answer 5

i gave u the expansion

Answer 6

why is the expansion of x^3-1 = (x^2+x+1)?

I am probably doing it wrong, but dont you pull out x-1 so you would have (x-1)(x^2-1)?

Answer 7

pull out x-1 then u have x^2+x+1

Answer 8

wait, if you pull out (x-1) is it (x-1)(x^2+1)?

Answer 9

\[=\ln (x-1)\]

Answer 10

correct?

Answer 11

yes abselutely