Question

3^X+3 - 9^2X-1=0
what are the steps to finding the solution?

Answer 1

\[3^x+3-9^{2x}-1=0?\]

Answer 2

Or!
Do you mean
\[3^{x+3}-9^{2x-1}=0\]

Answer 3

second one

Answer 4

Ok did you add to both sides \[9^{2x+1}\]

Answer 5

\[3^{x+2}=9^{2x+1}\]

Answer 6

oops - not +
oh well

Answer 7

Do you know how to answer the following
What number satisfies the equation
\[9=3^{?}\]

Answer 8

Ok great.
So we have
\[3^{x+2}=(3^{2})^{(2x-1)}\]
since 3^2=9 :)

Answer 9

So we have the same base on both sides
All you need to do is set the exponents equal and solve for x

Answer 10

\[x+2=2(2x-1)\]

Answer 11

Let me know if you have further questions :)

Answer 12

firstly its x+3 but where did you get the 2 in "2"(2x-1)

Answer 13

\[9=3^2 \]
\[3^{x+3}=9^{2x-1}\]
\[3^{x+2}=(3^2)^{(2x-1)}\]

Answer 14

how does 3^2(^2x-1) = 2(2x-1)

Answer 15

No....we have x+2=2(2x-1)
not what you wrote