Question

4/x=9/5 - 7x-4/5x

Answer 1

is this written as (4/x) = (9/5) - [(7x-4)/5x] ? not sure how to do it if it is written differently than what i am thinking of.

Answer 2

Multiply both sides by 5x to get

(5x)4/x = (9/5)(5x) - (4/5x)(5x)
20=9x-4
24=9x
24/9=x

Answer 3

Thanlk you I really dont understand though why did you multiply by 5/x

Answer 4

I multiplied both sides by (5x) and not (5/x) to get rid of the fraction

Answer 5

sorry im so stupid what happened to the 7

Answer 6

Sorry...I dropped it

Answer 7

by mistake

Answer 8

the answer is supposed to be 8

Answer 9

(5x)(4/x)=(9/5)(5x)-([7x-4]/5x)(5x)
20=9x-[7x-4]
20=9x-7x+4
20=2x+4
20-4=2x
16=2x
8=x

Answer 10

On the right side of the equation you need to make the denominator of both fractions the same. So since one already has 5x as the denominator you need to multiply (9/5) by x to get 9x/5x so you have

(4/x) = (9x/5x) - [(7x-4)/5x] then you have to combine the fraction into one since both denominators are the same. so you have

(4/x) = [9x-(7x-4)] / 5x distribute the negative...

(4/x) = (9x-7x+4) / 5x then combine like terms

(4/x) = (2x+4) / 5x now you can cross multiply

so you have 5x*4= x * (2x+4) then distribute only the left side to make things easier otherwise you will have a x^2 on the other side complicating things....so now you have

20x = x(2x+4) divide both sides by x

20 = 2x+4 subtract 4 on both sides

16 = 2x solve. x=8 hope this is the right answer and better explains things :]

Answer 11

thank you so much now if I can follow it thank you