Solve the quadratic equation by completing the square.
x2 + 6x + 7 = 0

Question

Solve the quadratic equation by completing the square.
x2 + 6x + 7 = 0

anonymous · Answer

To complete the square, use the fact that

x^2+bx=(x+0.5b)^2-0.25b^2

anonymous · Answer

Now re-write the equation as

(x^2+6x)+7=0

and you would notice that b=6

anonymous · Answer

I dont understand

anonymous · Answer

Alright....

x^2+6x+7=0
(x^2+6x)+7=0
[(x+3)^2-9]+7=0
(x+3)^2-2=0
(x+3)^2=2

anonymous · Answer

"Completing the square" operation is simply, whenever you see this term

x^2+bx (for any constant b), you can re-write it as

x^2+bx=[x+(b/2)]^2-(b^2/4)

anonymous · Answer

here you have the term 

x^2+6x 

which can be rewritten as

(x+3)^2-9

anonymous · Answer

Go here the answer is their! :) http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.7474.html

anonymous · Answer

Answer ---> (x+3)^2-16=0

anonymous · Answer

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