The figure below shows a Ferris wheel that rotates five times each minute. It carries each car around a circle of diameter 16.0 m.

----What force (magnitude and direction) does the seat exert on a rider when the rider is halfway between top and bottom, going up?

Question

The figure below shows a Ferris wheel that rotates five times each minute. It carries each car around a circle of diameter 16.0 m.

---->What force (magnitude and direction) does the seat exert on a rider when the rider is halfway between top and bottom, going up?

myname · Answer

is this the centripetal acceleration?

myname · Answer

?

anonymous · Answer

yes the acceleration is in the direction of the force.

anonymous · Answer

so I don't know if your question gives the mass, but if it does you should be able to multiply the mass times the acceleration.

myname · Answer

yes the mass of the rider is 52 kg

anonymous · Answer

oh hold on though don't plug that in.

anonymous · Answer

I think I gave you the wrong acceleration. a = v^2/r

anonymous · Answer

$$\frac{( r \omega)^{2} }{ r }$$

anonymous · Answer

$$r \omega ^{2} * m = F$$

anonymous · Answer

this final equation should give you the force.

myname · Answer

so v = r*w

anonymous · Answer

yes

anonymous · Answer

did you get the correct answer?

myname · Answer

No

myname · Answer

I got 114.04 N and it says my answer differs from the correct answer by more than  10%.

myname · Answer

Here, don't we find the force that is normal to the circle (wheel) at this point

myname · Answer

|dw:1350444215118:dw|

myname · Answer

We got the Fc which is 114.04 N

myname · Answer

Now if we get the tension force it will be great

anonymous · Answer

I'd have to see the drawing