Write the equation of the quadratic function with roots -10 and -8 and a vertex at (-9, -3).
Satellite pretty much showed you the format for this
is it the same for all?
Pretty much
still stumped...O.o
but ok
Here's what you can do with this information. If the quadratic has a root of x = k, then it has a factor of (x-k). i.e. for roots x = -10 and x = -8, the quadratic has factors (x+10)(x+8). There may still be an additional constant factor, a, so simplify y = a(x+10)(x+8) to get it in the form, ax^2+bx+c. With the additional information of a vertex at (-9, -3), then you can use the vertex form of the equation y=a(x-h)+k and put in your given information. The vertex is at (h, k), so y = a(x+9)^2 - 3. If you simplify that, you get y = ax^2 +18ax +81a -3. Compare that with the other equation to solve for a.
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