Question

What are the solutions?
16x^2 + 9 = 0

Answer 1

first add -9 to both sides
then divide both sides by 12

Answer 2

\[16x^{2} + 9 = 0 \]
\[16x^{2} =-9\]
\[x^{2} =\frac{-9}{16}\]
\[\sqrt{x^{2}} =\sqrt{\frac{-9}{16}}\]
\[x =\frac{\sqrt{-9}}{\sqrt{16}}\]
\[x =\frac{3i}{4}\]

Answer 3

do you understand it?

Answer 4

yea i do now

Answer 5

if i give you one to do will you be able to do it?