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Physics 14 Online
OpenStudy (anonymous):

It takes 29.5 days (2.55x10^6 s) for the moon to complete a full cycle. Mass of moon=7.35x10^22 kg. Radius from Earth to moon=3.85x10^8 m. Calculate the mass of the Earth using this information.

OpenStudy (anonymous):

Assuming it is making a circular motion, its aceleration is v^2/r, considering the formula for the force that a body makes in another equal to the force that the moon feels you can isolate the mass of earth. Is that clear?

OpenStudy (anonymous):

Kind of...

OpenStudy (anonymous):

In other words: \[F=ma=GMmr^{-2}\]And then the aceleration would be:\[a=GMr^{-2}\]

OpenStudy (anonymous):

So, big M is the mass of the Earth, and little m is the mass of the moon? And so I just solve for big M?

OpenStudy (anonymous):

Yes, and do you understand why the aceleration of the moon is v^2/r or Va*r, where Va is the angular velocity?

OpenStudy (anonymous):

Yes, I do

OpenStudy (anonymous):

Do I have to take that into account in solving the problem?

OpenStudy (anonymous):

well, that is the little a, so yes.

OpenStudy (anonymous):

Oh, now I understand. I solve little a, and then plug that into the equation to find M.

OpenStudy (anonymous):

Thats it.

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

Tour welcome

OpenStudy (anonymous):

So, v=2 pi r/T, right?

OpenStudy (anonymous):

For velocity, I got 9.49x10^14. And then, for acceleration, I got 2.34x10^37. Is that right?

OpenStudy (anonymous):

For my final answer, I got 5.2x10^42. Is that right?

OpenStudy (anonymous):

I got the same numbers but in very different scales, what units did you use?

OpenStudy (anonymous):

Just for you to know, I got 5.2x10^24Kg

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