A man kicks a soccer ball with a speed of 14 m/s at an angle of 40 degree (A)- how long does it take for the b all to reach the soccer goal if the young man is 9.85m away from it ?
I forgot what the equation is...help
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x= 9.85 = 14cos40 *t
so x is t which is 9.85?
the equation I'm using or was is V^2sin*2(40)/g
I'm still lost on it
I just need an equation and might of put the wrong one
x=V*t
\[x=x _{0}+V _{0x}t+\frac{ 1 }{ 2 }a _{x} t ^{2}\] from the previous image, we see the origin, therefore xo is 0, and there is no acceleration in the x direction, therefore 1/2 at^2 is zero so x = Vcost theta * t
yes, yu can also use t= V^2Sin theta over g it shud give the same answer
okay well I just want to see if its right
yes it is,
I'm gonna solve it and give you the answer just see if I'm right or wrong
I got 14.9...yes or no?
I did 14^2 which is 196sin (40) / 9.8
so 9.8 seconds?
no, it is 0.92 seconds, use the \[t = \frac{ 9.85 }{ 14\cos 40 }\]
ahhh! I did it backward ugh
I don't see how I'm getting -.469
in my calculator i put in 9.85 / 14cos(40)
make sure your calculator is in degree mode,
https://www.desmos.com/calculator, yu can use that, make sure the settings is in degree mode
yeah well I'm putting even in putting in degree mode I got .539
I'm gonna try it on an online calculator
good well I got it on here well I need help solving another
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