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Mathematics 9 Online
OpenStudy (anonymous):

In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (4,0), (6,3) and (6,-3)? forget the formula please help...!!

OpenStudy (anonymous):

draw the points...u'll get the answer

OpenStudy (anonymous):

i mean on xy plane

OpenStudy (nubeer):

manitude =\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\] draw the rectangle .. find the magnitude of two sides.. apply the formula or rectangle.

OpenStudy (anonymous):

|dw:1350453626580:dw|

OpenStudy (anonymous):

|dw:1350453688691:dw|

OpenStudy (anonymous):

so area= 1/2*6* 2

OpenStudy (anonymous):

i want to know that formula 1/2(x1(y2-y1)+x2(y3-y2)+x3(y2-y1)) is that correct?

OpenStudy (anonymous):

these all take time

OpenStudy (anonymous):

formula is 1/2 { x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}

OpenStudy (anonymous):

ok

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