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In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (4,0), (6,3) and (6,-3)? forget the formula please help...!!
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draw the points...u'll get the answer
i mean on xy plane
manitude =\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\] draw the rectangle .. find the magnitude of two sides.. apply the formula or rectangle.
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so area= 1/2*6* 2
i want to know that formula 1/2(x1(y2-y1)+x2(y3-y2)+x3(y2-y1)) is that correct?
these all take time
formula is 1/2 { x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}
ok
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