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OpenStudy (anonymous):
\[y=1/x(x+1)(x+2)\]
OpenStudy (amorfide):
|dw:1350454366994:dw|
this?
OpenStudy (anonymous):
sorry...1 is the numerator...everything else in the den.
OpenStudy (amorfide):
do you know the chain rule?
OpenStudy (anonymous):
y=1/(x(x+1)(x+2))
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OpenStudy (anonymous):
I pretty much know nothing for my calc class. I just need to get through this assignment that's due tomorrow and then I start my sessions with my tutor...any help is greatly appreciated
OpenStudy (mimi_x3):
\[\large \frac{1}{x(x+1)(x+2)} \]
OpenStudy (mimi_x3):
well you can use the product rule or the quotient rule
OpenStudy (mimi_x3):
have you tried expanding it
OpenStudy (anonymous):
So...1\[\frac{ 1 }{ x ^{3}+3x ^{2}+2x}?\]
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OpenStudy (amorfide):
you could bring it to the top, so all the powers change signs to a negative
OpenStudy (anonymous):
\[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }..???
OpenStudy (anonymous):
sorry...that's so ugly. I'll retype it.
OpenStudy (anonymous):
\[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }\]