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use logarithmic differentiation to find the derivative of y with respect to x:
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\[y=\sqrt[3]{\frac{ x(x+1)(x-2) }{ (x ^{2}+1)(2x+3)}}\]
ln[y] = (1/3) ln [ (x(x+1)(x-2)) / ((x^2+1)(2x+3)) ] take the derivative now : (dy/dx) / y = (1/3) * [ (x(x+1)(x-2)) / ((x^2+1)(2x+3)) ]' / y^3 can you do it now ?
Yep...thank you! :)
yw. Im glad you can, this is a lot of work
Even more work if logarithmic differentiation is not allowed :D
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