Question

Find the slope, if it exists, of the line containing the pair of points (-12,-16) and (-13,-19)

Answer 1

m=(y2-y1)/(x2-x1)
x1=-12,y1= -16
x2=-13,y2=-19
just plug in the values .. you will get the slope.

Answer 2

@mathgirl501

Answer 3

so would it be 1,13

Answer 4

?

Answer 5

@nubeer

Answer 6

or am i way off? I'm no good with math sorry

Answer 7

you have to find the slope.. and there can't be 2 values of the slope

Answer 8

well plug in the values in the formula i told above..

Answer 9

\[m=\frac{ y2-y1 }{ x2-x1 }\]

Answer 10

well i did that and came up with 1 and 13...is it supposed to be a fraction

Answer 11

hmm well lets do again..
\[m=\frac{ -19-(-16) }{ -13-(-12) }\]
tell me do u get this part? did u do it same way when you solved it?

Answer 12

yes

Answer 13

13-12=1

Answer 14

ok tell me what u got in numerator and denominator?

Answer 15

thats how i got that

Answer 16

infact its not 13-12
its -13-(-12) which is -13+12.. do u get it?

Answer 17

oh ok I see

Answer 18

ok now do it for the numerator..

Answer 19

-19+16=-3

Answer 20

ok good..
now tell me what fraction u have left?

Answer 21

-3 in numerator and -1 in denominator..

Answer 22

ok so i do subtract, i was thinking to add

Answer 23

thanks

Answer 24

you just have to be carful with the signs.. where to add and where to subtract so tell em what is slope?

Answer 25

would it be -3

Answer 26

hmm no .. look again u have -3 in numerator and -1 in denominator. so it looks like \[\frac{ -3 }{ -1 }\]
minus sign will be cancelled.. so your slope will be 3..

Answer 27

ok I get it now thanks for your help

Answer 28

hope u understand it.. and you're welcome. ..