Let:
x = number of books borrowed by a student in a term

x = "uniformly distributed" from x = 0 to 10

What is the probability that a randomly selected student has borrowed at most 3 books?

Question

Let:
x = number of books borrowed by a student in a term

x => "uniformly distributed" from x = 0 to 10

What is the probability that a randomly selected student has borrowed at most 3 books?

parthkohli · Answer

4/11 would be my guess.

lgbasallote · Answer

why so?

parthkohli · Answer

This probability doesn't have to do anything with "a randomly selected student". So, from the definition of probability, we have 4 ways to select at most 3 books.

First way: 0 books
Second: 1 book
Third: 2 books
Fourth: 3 books

The number of ways to select books is eleven. 

First: 0 
Second: 1
.
.
.
Eleventh: 10

parthkohli · Answer

So, 4/11.

parthkohli · Answer

Might be a twisted question, but still...

lgbasallote · Answer

what do you mean it doesn't have anything to do with the randomly selected?

parthkohli · Answer

That's because selecting a student is totally independent of the number of books he has.

lgbasallote · Answer

hmm

lgbasallote · Answer

...something doesn't feel right...

parthkohli · Answer

What doesn't?

hartnn · Answer

3/10

hartnn · Answer

this is discrete math right ? i used integration to get 3/10

hartnn · Answer

$$\int\limits_{0}^{3}\frac{ 1 }{ 10-0 }dx$$

lgbasallote · Answer

1) It's not discrete math
2) Discrete math doesn't use those snakes
3) 4/11 is the right answer

hartnn · Answer

ok.

lgbasallote · Answer

by the way...friendly advice @hartnn solutions before answers....it will help you keep the moderators off your tail

parthkohli · Answer

Yay! I was right!

hartnn · Answer

i will keep that in mind. thanks :)