Find the exact value of 2sec(π/4) + 4cot(π/3). Do I find cos(π/4) & tan(π/3)?
yes...
cos(π/4)= sqrt2/2 & tan(π/3)= sqrt3, right?
yes... so just take the reciprocals and replace them in your original problem.
Do I ignore sec & cot, sorry, I just learned this today.
no... \(\large cos\frac{\pi}{4}=\frac{\sqrt2}{2} \) so this means: \(\large sec\frac{\pi}{4}=\frac{2}{\sqrt2} \)
Right, I got that.
So far.
and since \(\large tan\frac{\pi}{3}=\sqrt3 \) then \(\large cot\frac{\pi}{3}=\frac{1}{\sqrt3} \) plug these values into the original problem
\(\large 2sec\frac{\pi}{4}+4cot\frac{\pi}{3}=2(\frac{2}{\sqrt2})+4(\frac{1}{\sqrt3}) \)
first one is (1/ (cos (pie/4)))*2 = 2 *under root 2 second one (1/tan(pie/3))*4 =4 under root 3 5.14 is the answer :D
Thanks you guys, but ByteMe, wouldn't I rationalize & then solve?
also divide by 3|dw:1350474625133:dw|
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