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OpenStudy (mazehaq):
Find the exact value of 2sec(π/4) + 4cot(π/3).
Do I find cos(π/4) & tan(π/3)?
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OpenStudy (anonymous):
yes...
OpenStudy (mazehaq):
cos(π/4)= sqrt2/2 & tan(π/3)= sqrt3, right?
OpenStudy (anonymous):
yes... so just take the reciprocals and replace them in your original problem.
OpenStudy (mazehaq):
Do I ignore sec & cot, sorry, I just learned this today.
OpenStudy (anonymous):
no...
\(\large cos\frac{\pi}{4}=\frac{\sqrt2}{2} \)
so this means:
\(\large sec\frac{\pi}{4}=\frac{2}{\sqrt2} \)
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OpenStudy (mazehaq):
Right, I got that.
OpenStudy (mazehaq):
So far.
OpenStudy (anonymous):
and since
\(\large tan\frac{\pi}{3}=\sqrt3 \)
then
\(\large cot\frac{\pi}{3}=\frac{1}{\sqrt3} \)
plug these values into the original problem
OpenStudy (anonymous):
\(\large 2sec\frac{\pi}{4}+4cot\frac{\pi}{3}=2(\frac{2}{\sqrt2})+4(\frac{1}{\sqrt3}) \)
OpenStudy (anonymous):
first one is (1/ (cos (pie/4)))*2 = 2 *under root 2
second one (1/tan(pie/3))*4 =4 under root 3
5.14 is the answer :D
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OpenStudy (mazehaq):
Thanks you guys, but ByteMe, wouldn't I rationalize & then solve?
OpenStudy (anonymous):
also divide by 3|dw:1350474625133:dw|
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