Question

cosx/sin^2(x)-1

Answer 1

use the identity
\(\huge sin^2x+cos^2x =1\)
so what is
cos^2x-1 from here ?

Answer 2

sorry, what is sin^2x-1 from that ?

Answer 3

and i assume the question is :
\(\huge \frac{cos x }{sin^2x-1}\)

Answer 4

Yes, that is the question. Sorry I just found this website and I haven't done math like this in years. Would it be equal to \[-\cos ^{2}x\]

Answer 5

that is correct!
so u have \(sin^2 x -1 = - cos^2 x\)
now put that in your original question expression and how can u simplify that, any ideas ?

Answer 6

(-cosx) (cosx) ???

Answer 7

u get
\(\huge \frac{cos x }{sin^2x-1} = \frac{cos x}{-cos^2x}\)
which gets simplified to ?

Answer 8

doesn't cos x from numerator get cancelled with one of th cos x from denominator ?

Answer 9

yes, thank u

Answer 10

so finally ,did u get -sec x ?
and
\(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\)

Answer 11

Thank you SO much!

Answer 12

welcome ^_^