PLEASE HELP IF YOU CAN! I did the equation the right way. At least, I think I did the equation the right way. When I look at the textbook, it says I did the equation the right way. But my teacher says I got it wrong. I had to find the slope of a line. Point A(-1, 4), Point B(3, 1), and Point C(0,-3). The slopes I had to find were Line AB, Line AC, and Line BC. For AB=3/4 AC=-1 BC=-4 If you could please help me and tell me where I went wrong and how to do it correctly, it would mean the world to me! PLEASE
How did you get 3/4 for slope of AB?
4-1/3-(-1)
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If you use [3 - (-1)] in the denominator, then the numerator must be [11 - 4]
Your slope for AC is correct, but BC can't have a negative slope: it is going up and to the right.
Hmm, okay... So, how do I fix AB and BC?
Look at the picture I drew (or better yet, draw your own on some paper in front of you) and look at the 'rise-over-run.'
Hang on....You said that the numerator for AB would have to be (11-4)...where'd you get the 11?
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