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Chemistry 19 Online
OpenStudy (anonymous):

How many grams of CaCl2 is 0.245 mol CaCl2?

OpenStudy (australopithecus):

Just use the equation \[Mole = \frac{Gram}{Molecualr Mass}\] so added the molecular mass of Calcium with 2 times chlorine's molecular mass, which is listed on a periodic table

OpenStudy (australopithecus):

add*

OpenStudy (anonymous):

CaCl2 is equal to 110.984 grams

OpenStudy (australopithecus):

do you not know how to do the algebra?

OpenStudy (australopithecus):

sub in moles and molecular mass into the equation then multiple both sides by the molecular mass to isolate grams

OpenStudy (australopithecus):

remember the units for molecular mass are g/mol

OpenStudy (anonymous):

ok, therefore .245=110.984/0.125, correct?

OpenStudy (anonymous):

then you cross multiply and divide the numerator by the denominator which equals to .000275

OpenStudy (australopithecus):

Not sure what you are doing 0.245 mol = grams/(110.984g/mol) (0.245 mol)(110.984g/mol) = ( (110.984g/mol)grams )/(110.984g/mol) (110.984g/mol)(0.245 mol) = grams(1) (110.984g/mol)(0.245 mol) = grams

OpenStudy (australopithecus):

if you notice units cancel out and you are left with 27.19g or in significant figures 27.2g

OpenStudy (australopithecus):

CaCl2 has a molecular mass of 110.984g/mol Grams = ? Moles = 0.245mol sub into equation and solve for grams

OpenStudy (australopithecus):

which I did above

OpenStudy (jfraser):

do the same thing you did last problem, just upside down

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