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Calculus1
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let f be a function defined by f(x)=ax^2+bx+c with the following properties: f(0)=2; f'(2)=10; f''(10)=4. find the values of a, b, and c
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So f(0) = 2 = c (Sub x = 0) f' = 2ax + b -> f'(2) = 10 = 2ax +b etc U can finish it off, no?
f'(x) = 2ax+b f''(x) =2a f(0)=2 c=2 f''(10) = 2a=4. a=2 f'(2) = 4a+b. 4(2)+b=10. b=2 f(x) = 2x^2+2x+2
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