Radical question. calculate the length of the diagonal of a square with side length 4cm. the answer is 4sqaureroot2 but i dont know how to get it
use pythagoras, but only once
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by pythagoras, \[a^2+a^2=h^2\]\[2a^2=h^2\]\[\sqrt{2a^2}=h\]\[\sqrt{2}a=h\]
so whatever \(a\) is, (in your example it is 4) if \(a\) is the side of a square, then the length of the diagonal is \(a\sqrt{2}\)
by "only once" i mean once you do it with a variable \(a\) you do not need to redo it with 4 or 5 or 10 if the length of the side of a square is 10, then the length of the diagonal is \(10\sqrt{2}\)
Thanks :)
What about determine the length of the diagonal rectangle with dimensions 3cm x 9cm
again pythagoras \[d^2=3^2+9^2\] \[d^2=9+81=90\] \[d=\sqrt{90}=\sqrt{9\times 10}=3\sqrt{10}\]
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