Question

Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).

Answer 1

\[4Li _{(s)}+O _{2}(g) \rightarrow 2Li _{2}O _{(s)}\]

Answer 2

Really need help trying to understand redox reactions.

Answer 3

http://answers.yahoo.com/question/index?qid=20100215222246AA9pFud

this misht help you :)

Answer 4

thanks didn't try yahoo yet

Answer 5

no problem

Answer 6

Li is being oxidized and thus is the reducing agent

i know this because oxygen always has a -2 oxidation state and since it's oxidation state in diatomic oxygen is zero, it was reduced, and so oxygen is the oxidizing agent