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OpenStudy (anonymous):

Oxidation number of Cr(OH)3?

OpenStudy (kainui):

Oxygen gives -2 and hydrogen +1 to the oxidation state. Since the molecule above is neutral, as in it doesn't have a charge like Na+ or something we can tell that the oxidation of the Chromium is equal but opposite to the oxygen and hydrogen to balance out. So first off, find out the total contributions from the oxygen and hydrogen.

OpenStudy (australopithecus):

|dw:1350526298566:dw| oxidative number = 0

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