Question

use the chain rule to find the derivative of f(x)=x^2(x-2)^4

Answer 1

ap calc? i'm doing the same thing -____-
anyways, chain rule is h'(x) = f'g x g' sooo

h'(x) = \[4x ^{2}(x-2)^3 \times 1\]

Answer 2

well supposedly the answer is \[2x(x-2)^3(3x-2)\]

Answer 3

Hmmm looks like the product will be useful here! c:

Answer 4

Hmmm so there's the setup that we want for product rule.
Now we need to take the derivative of the things with primes on them.