Ask your own question, for FREE!
Chemistry 12 Online
OpenStudy (anonymous):

If the concentration of Na3PO4 in a solution is 0.11 M and there is 31mL of solution, how many sodium ions are in the solution?

OpenStudy (australopithecus):

First find the moles present in the solution next create a ratio of molecular masses and multiply it by the moles in solution (Molecular Mass of Na3/Molecular Mass Na3PO4)(moles of Na3PO4 in solution)

OpenStudy (australopithecus):

this will give you the moles of sodium in solution

OpenStudy (australopithecus):

any questions?

OpenStudy (australopithecus):

Oh and if you didn't know Molarity = Moles/Litres of total solution

OpenStudy (australopithecus):

1000mL = 1L

OpenStudy (anonymous):

Thanks man, appreciate it! Had no idea where to even start.

OpenStudy (australopithecus):

yeah you can just use molecular mass ratios to solve these problems, if you were trying to figure out the total moles of the compound from the sodium ions you would just flip the ratio

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!