could someone please help me with these two.. ): i'm studying for a test and i got stuck with these too.. i don't want to skip it because it might be on the test.

solve.
$$4^{5x} = 16 ^{2x-1}$$
and
$$3^{5x}9^{x ^{2}} = 27$$

Question

could someone please help me with these two.. ): i'm studying for a test and i got stuck with these too.. i don't want to skip it because it might be on the test.

solve. 
$$4^{5x} = 16 ^{2x-1}$$
and 
$$3^{5x}9^{x ^{2}} = 27$$

anonymous · Answer

Hint: 16 = 4²

anonymous · Answer

27 = 3³

anonymous · Answer

@alexeis_nicole smart move! it's highly chance to be on the test :)

anonymous · Answer

ohh. okay so for the first one... 
would it be $$4^{5x} = 4^{2(2x-1)}$$$$4^{5x} = 4^{4x-2}$$$$5x=4x-2$$$$5x-4x=-2$$$$x=-2$$

right??? :)

anonymous · Answer

Perfect :)

anonymous · Answer

yay ! k i'll try the next one then get back to you (x

anonymous · Answer

k.. uh... what do i do with the $$x^2$$ in the second equation ?? :S

anonymous · Answer

9 = 3²

anonymous · Answer

soo... am i supposed to get 5x + 2x^2 = 3 ? :S

anonymous · Answer

Yes, can you solve 2x² + 5x - 3 = 0

anonymous · Answer

uhmmm.. id just factor this right?
sorry,, i just got lost Dx

anonymous · Answer

5x + 2x² = 3
2x² + 5x - 3 = 0
Can you apply quadratic formula?

anonymous · Answer

i applied the quadratic formula and i got 3, and -0.5

anonymous · Answer

oH WAIT... i did something wrong.. let me try that again )x sorry!

anonymous · Answer

i got 0.5 and -3.

anonymous · Answer

Correct now :)

anonymous · Answer

so... would that be the answer? :S

anonymous · Answer

Yes!

anonymous · Answer

hmm... :/ the book tells me that its supposed to be -.02 ?

anonymous · Answer

If so, check your post?

anonymous · Answer

hmm... its the right equation... /:

anonymous · Answer

If your post correct, then the solution has typo! Point it out to your teacher :)

anonymous · Answer

hmm probably. yeah i will, thank you :)

anonymous · Answer

Be confident ;)