2[a(a + b) + b(a + b)]
can anyone help me
yes tell me, do u want to simplify this equation ? If yes then it comes out to be \[2(a+b)^2\] It can be also written as \[2a^2+4ab+2b^2\]
can u show me in steps please
where did u get the 4 from
ok wait
We have, 2[a(a + b) + b(a + b)] Let 2 be outside the square brackets and we will solve the part inside the square brackets, \[2[a^2+ab+ab+b^2]\] Now, solving further \[=2 [ a^2 + 2ab + b^2 ]\] \[=2(a+b)^2\] (because we are aware about this algebraic identity \[(a+b)^2=a^2+2ab+b^2\] )
2[a(a + b) + b(a + b)] from here you can factor out a+b, this becomes =2(a+b)[a+b] and just like Sid has said it became =2(a+b)^2 di you see it A candi?
so what would the answer b
is there any answer selection?
no solve till i cant brake it dwn anymore
wher does the 4 come from
Ok I'll tell you, When you solve this \[2(a^2+ab+ab+b^2)\]\[=2(a^2+2ab+b^2)\]\[=2(a^2)+2(2ab)+2(b^2)\]\\[=2a^2+4ab+2b^2\] Is it clear now that where did 4 come from ?
the 4 came from 2(2ab)=4ab
Yes you are right
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