Question

Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
y sin 12x = x cos 2y, (π/2, π/4)

Answer 1

apply chain rule

Answer 2

I got y'= (cos2y-12cos12x) / (sin12x+2xsin2y)

Answer 3

I solved for slope and got 12/pi

Answer 4

Correct me if I'm wrong.

Answer 5

y'sin12x + 12ycos12x = cos 2y -2xy'sin2y

Answer 6

yeah and when you solve for y' it's equal to (cos2y-12cos12x) / (sin12x+2xsin2y) right?

Answer 7

ur missing a y in ur numerator

Answer 8

y' = (cos2y - 12ycos12x)/ (sin12x + 2xsin2y)

Answer 9

Thanks. Lemme solve the rest of the problem and see what I would come up with for the slope.

Answer 10

np

Answer 11

y'=3?

Answer 12

im getting -3