Question

Use the properties of logarithms to expand the expression ln z(z-1)^2, z>1?

Answer 1

Check it on yahoo . It says " = Ln (z) + Ln (z-1)^2
= Ln (z) + 2 Ln (z-1) "

Answer 2

that's the question I posted

Answer 3

and no one would explain

Answer 4

amofide xD

Answer 5

you have rules for logs
if you have

lnx²
that is the same as saying
2lnx

you can bring the power to the front of the log

Answer 6

but how do you separate it? Like Ln (z) + Ln (z-1)^2

Answer 7

i mean Ln (z) + 2 Ln (z-1)

Answer 8

also
you started with
ln z(z-1)^2

there is another rule for logs

if you have

lna + ln b this is equal to
lnab

so you have

ln z(z-1)^2


this is being multiplied, so we know we have two logs added together

lnz + ln (z-1)²

Answer 9

Ooooooooooooooh

Answer 10

Thanks!

Answer 11

anytime :D

so

lna+lnb=lnab

lna-lnb=lna/b

lna^b=blna

i think there is another one i forget...