Ideal Gas Law Question:
Under 371.5K and .9949 atm, would methanol vapor (with .04g and a volume of .01275 L) and isopropanol vapor ( .11g and a volume of .01250 L) behave as an ideal gas?

Question

Ideal Gas Law Question:
Under 371.5K and .9949 atm, would methanol vapor (with .04g and a volume of .01275 L) and isopropanol vapor ( .11g and a volume of .01250 L) behave as an ideal gas?

anonymous · Answer

$$Z=\frac{ PV}{ NRT }$$

If Z=1 then the gas is Ideal..

anonymous · Answer

Nop....

moles = given mass/molar mass

anonymous · Answer

So does it have to be exactly 1 to be ideal?

anonymous · Answer

i have nt Solved...I Just gave u the equation u have to Solve this... i will help if u get stuck....

anonymous · Answer

Lol......Mass of Methanol is given as 0.4g u have to find its Molar Mass

anonymous · Answer

Formula CH3OH...nw find its MM

anonymous · Answer

ok but is the gas ideal only if the answer is exactly 1?

anonymous · Answer

Or if u get 0.97 , 0.99 or 95....then also....U can Aprrox it

xishem · Answer

The reason only the value of 1 works is because the expression is derived from the ideal gas equation:$$PV=nRT \rightarrow 1=\frac{nRT}{PV}$$You could also just plug in numbers into the original ideal gas equation, and if both sides of the equation come out equal, then that means that the gas follows the parameters of the ideal gas equation, making it an ideal gas.

xishem · Answer

On the other hand, if you get something like 1=2, then the gas obviously doesn't follow the ideal gas equation.