Question

Ideal Gas Law Question:
Under 371.5K and .9949 atm, would methanol vapor (with .04g and a volume of .01275 L) and isopropanol vapor ( .11g and a volume of .01250 L) behave as an ideal gas?

Answer 1

\[Z=\frac{ PV}{ NRT }\]

If Z=1 then the gas is Ideal..

Answer 2

Nop....

moles = given mass/molar mass

Answer 3

So does it have to be exactly 1 to be ideal?

Answer 4

i have nt Solved...I Just gave u the equation u have to Solve this... i will help if u get stuck....

Answer 5

Lol......Mass of Methanol is given as 0.4g u have to find its Molar Mass

Answer 6

Formula CH3OH...nw find its MM

Answer 7

ok but is the gas ideal only if the answer is exactly 1?

Answer 8

Or if u get 0.97 , 0.99 or 95....then also....U can Aprrox it

Answer 9

The reason only the value of 1 works is because the expression is derived from the ideal gas equation:\[PV=nRT \rightarrow 1=\frac{nRT}{PV}\]You could also just plug in numbers into the original ideal gas equation, and if both sides of the equation come out equal, then that means that the gas follows the parameters of the ideal gas equation, making it an ideal gas.

Answer 10

On the other hand, if you get something like 1=2, then the gas obviously doesn't follow the ideal gas equation.