Question

A particle is projected vertically upwards from ground is at same height after 1.5s and 6.5s of projection . The maximum height reached by the projectile is (g=10m/s^2)?

Answer 1

confused

Answer 2

But in Second Case The projectile is Coming Down..

Answer 3

a is -g for all cases

Answer 4

let initial velocity be u

it takes 5 secs to come back to same point from that point
thus it takes 2.5+1.5 or 4 secs to reach topmost point

and thus

h = 1/2 g(4^2) ...for decending..

Answer 5

ans = 80

Answer 6

am sorry,,no need to let initial velocity u,,theres no use of it in my method..

Answer 7

i missed to include this :
since it takes 4 secs to reach topmost point, hence it'll take 4 secs to reach back to initial point..

Answer 8

thxx...

Answer 9

you may also see it as


total time =8
hence, time of descending = 4

Answer 10

you're welcome,,glad to help..