Question

Find the intersection point between two lines:
L1=<-3,5,7>k+<1,-2,-0>
L2=<3,-1,-4>t+<1,2,3>

Answer 1

just equate the values of x, y, z from those two lines and find the valeus of k and t.
if you don't find singular values ... then they do not intersect.

Answer 2

Hey @experimentX . I tried solving this intersection using a similar method you showed me for the line and plane intersection, does it work here as well?

Answer 3

Yeah, I found the intersection using the x,y,z components from L1 and L2 and found the correct intersection. I was just wondering if we could solve it using the other way you showed me for the line and plane problem

Answer 4

yeah it works .... just try to find the value of k and t ... from first two equation. put the value on the last equation. If it's invalid then the line does not intersect.

Answer 5

Okay, so far I have from L2:
1+3t -->k1
2-t ---->k2
3-4t--->k3

and L1:
-3k1+5k2+7k3=1

Filling those values from L2 into L1, I get:

1=-3(1+3t)+5(2-t)+7(3-4t)
1=-3-9t+10-5t+21-28t
t=27/42

Answer 6

lol ... what are you doing??