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Mathematics 18 Online
OpenStudy (marg):

A car traveling at 7.5 m/s accelerates 2.2 m/s^2 to reach a speed of 17.0 m/s. How long does it take for this acceleration to occur? Answer in units of s

OpenStudy (anonymous):

s = 52.90 m

OpenStudy (anonymous):

acceleration equals change in velocity divided by change in time.

OpenStudy (anonymous):

@zainulanwar that does not properly answer the question (not only is it just plain wrong, but it doesn't offer any explanation.)

OpenStudy (marg):

how do you find the change in velocity?

OpenStudy (anonymous):

Subtraction.

OpenStudy (marg):

so 7.5 -2.2?

OpenStudy (anonymous):

2.2 is an acceleration not a velocity, you can't add or subtract unlike terms.

OpenStudy (anonymous):

Always include the units with your numbers while doing calculations, that will keep you on the right track.

OpenStudy (marg):

17m/s-7.5m/s then?

OpenStudy (anonymous):

Right. Difference is always (final) - (initial).

OpenStudy (marg):

im confused on what to do next after you find that

OpenStudy (anonymous):

Using the definition, acceleration equals change in velocity divided by change in time. \[\large a = \frac{\Delta v}{\Delta t}\] Solve for t by rearranging the equation \[\large \Delta t = \frac{\Delta v}{a}\]

OpenStudy (marg):

would it be 4.318 s?

OpenStudy (anonymous):

Yes, and you can round that off to 4.3 s because you are limited to two digits of precision from the given values.

OpenStudy (marg):

thank you soooo much:)

OpenStudy (anonymous):

You're welcome. I hope it makes more sense now.

OpenStudy (marg):

it does:) i get it a lot more than i did

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