Question

Find the absolute minimum and absolute maximum values of f on the given interval.
f(x) = (x^2− 1)^3, [−1, 4]

Answer 1

\[f'(x)=3(x^2-1)^2\times 2x\] by the chain rule
set equal to zero and solve, then check the zeros and the endpoints to see what is biggest and what is smallest

Answer 2

don't forget that last step
you need \(f(-1), f(4)\) as well as the zeros of the derivative

Answer 3

okay, I'll try. thank you!