Find the critical numbers of the function. g(x) = square root of (1 − x^2)
You can get the y and x intercepts and maximum y value either through algebra or with differential calculus. Which do you prefer?
I'm in calculus
Max can be gotten through algebra by completing the square method. Calculus by differentiating and setting the first derivative to 0 and either 1) seeing whether the slope of the derivative goes from + to - or - to + or 2) taking the second derivative to see if the curve is concave up or down. Just got your post and see that you want calculus. Okay.
Can you calculate the first derivative or do you need help with that part?
If you can help that would be great. I'm not great with derivatives.
Okay, keeping with the spirit of this site, I'm going to give you some formulas to work instead of just handing out an answer. Your equation is a polynomial which you can break up into terms and take the derivative of each term and add them. The first term is "1" which is a constant and the derivative of a constant is 0, so just look at the second term. if y = ax^n, then y' = anx^(n-1). Show your work.
Do you know the chain rule?
yes
y' = [(1/2)(1 - x^2)^(-1/2)](-2x). Do you see how I got that? Still needs a little simplifying.
Yeah, I see where I went wrong now thought. I forgot the -2x
So, y' = -x(1 - x^2)^(-1/2). Okay, you say you see now where you went wrong. Are you all set now or need further help?
I think I've got it now, thank you!
Good luck to you on all your studies!
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