Calculate the derivative: dP/dV where v=-2 and p=4/v no idea how to start this one.
can u calculate d/dv(v^n) ?
\[nx ^{n-1}\]
right :) \(so\quad d/dv(1/v) = d/dv(v^{-1})=?\)
-v^-2?
that is correct ! :) so \(d/dv(4/v)= 4 d/dv(1/v)=?\)
because 4 is a constant and can be taken out from derivative
=4
dP/dv = d/dv(4/v) = 4 d/dv(1/v) = 4 \((-v^{-2})\) got this ? now just put v= -2 here
??
that all equals one, right?
4(-v^-2) = 4(2^-2)=4 times 1/4 = 1
\(\huge4(-(-2)^{(-2)})= -4(\frac{1}{(-2)^2})=\frac{-4}{4}=?\) u just missed a - *minus* sign
shouldn't that be a pus 2?
-v = -(-2) = 2
but the derivative, does not contain -v derivative is \(\huge -v^{-2}= -\frac{1}{v^2}\)
so the derivative of v=-1
derivative of v will be +1 but why do u need derivative of v ?
the question is the derivative of dP/dV and you told me to get the derivative of v .. and i said it was plus one then you said i was wrong and that it's -4/4
im just trying to find out the answer haha.
i never said that derivative of v , +1 is wrong....
im confused as to what you are trying to get me to do then.
i just said that u missed a minus sign here "4(-v^-2) = 4(2^-2)=4 times 1/4 = 1 " it should be 4(-v^-2) = 4(-(-2)^-2)=4 times (-1/4) = -1 got this ?
sorry, if i confused you....
and is that the derivative for v?
u need to calculate derivative of P, dP/dv which we worked out as -1 and thats the final answer we don't need derivative of v here(which is 1 bdw)
so my answer is -1?
YES ! :)
thank you so much !!!
thankss
welcome ^_^
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