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OpenStudy (anonymous):
Am I to assume A=D B=E C=F
OpenStudy (anonymous):
180 = (3y) + (6y-12) + m<C
OpenStudy (anonymous):
I'm still thinking
OpenStudy (tyteen4a03):
@ChmE When given a set of congruent triangle (e.g ABC and DEF), it implies that A=D, B = E and C = F.
OpenStudy (anonymous):
I was just dbl checking because I have 1 equation and 2 unknowns right now.
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OpenStudy (anonymous):
6y-12=3y then solve
OpenStudy (anonymous):
@lexiamee I don't think <D and <B are congruent here.
OpenStudy (anonymous):
thats the only way I can think to solve
OpenStudy (anonymous):
Yeah, it's tempting to make that assumption. I think we need more information.
Is there any other information, @Figureskater120 ? Was there a diagram to go with this?
OpenStudy (anonymous):
Seems that way. Might have to assume that m<B = m<D, otherwise, the best you can do is get a range of possible values.
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OpenStudy (anonymous):
equal them to each other , so :
6y - 12 = 3y
then subtract 3y from 6y, and add 12 to the other side :
6y - 12 = 3y
-3y +12 -3y
--------------
3y = 12
divide 12 by 3
y = 4