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Geometry 9 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Am I to assume A=D B=E C=F

OpenStudy (anonymous):

180 = (3y) + (6y-12) + m<C

OpenStudy (anonymous):

I'm still thinking

OpenStudy (tyteen4a03):

@ChmE When given a set of congruent triangle (e.g ABC and DEF), it implies that A=D, B = E and C = F.

OpenStudy (anonymous):

I was just dbl checking because I have 1 equation and 2 unknowns right now.

OpenStudy (anonymous):

6y-12=3y then solve

OpenStudy (anonymous):

@lexiamee I don't think <D and <B are congruent here.

OpenStudy (anonymous):

thats the only way I can think to solve

OpenStudy (anonymous):

Yeah, it's tempting to make that assumption. I think we need more information. Is there any other information, @Figureskater120 ? Was there a diagram to go with this?

OpenStudy (anonymous):

Seems that way. Might have to assume that m<B = m<D, otherwise, the best you can do is get a range of possible values.

OpenStudy (anonymous):

equal them to each other , so : 6y - 12 = 3y then subtract 3y from 6y, and add 12 to the other side : 6y - 12 = 3y -3y +12 -3y -------------- 3y = 12 divide 12 by 3 y = 4

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